I have a list of objects stored in an array where each object holds unique numeric properties. In the example below, the array contains four items with properties named x and y. I am specifically looking to extract the third object in the list—that is, the one where the property y equals 60—without resorting to a for…in loop. Can someone propose an efficient JavaScript technique that locates and returns this object by evaluating its property value?
let itemArray = [
{x: 10, y: 20},
{x: 30, y: 40},
{x: 50, y: 60},
{x: 70, y: 80}
];
hey, try using array.find like: let result = itemArray.find(obj => obj.y === 60); it’s super eazy and avoids using a loop
An alternative to using array.find is to combine the findIndex method with direct array indexing. For instance, by writing let index = itemArray.findIndex(element => element.y === 60) you retrieve the index of the desired object, and then you access it using itemArray[index]. This approach is particularly useful when you also need to know the position of the object within the array, which can be helpful in scenarios involving further updates to the array. I have applied this strategy in similar situations and found it both clear and efficient.
In one of my recent projects I used the reduce method to achieve a similar result. I was facing a situation where I needed to retrieve an object from an array based on a property while also aggregating some related data. I wrote something like: itemArray.reduce((found, current) => { return current.y === 60 ? current : found; }, null) so that the process stops after finding the matching element. This method integrates data transformation into the search in a concise manner and can be adapted if more complex logic is needed.