Hey everyone,
I’m building an app that uses the Google Drive API. I want users to be able to make files that anyone can see without needing permission.
I’ve found some examples of how to create files with the API. But I’m stuck on how to make them public right away. Is there a way to set file permissions to ‘public’ when you first upload it?
Here’s a bit of code I’m working with:
def create_public_file(service, file_name, file_content):
file_metadata = {'name': file_name}
media = MediaIoBaseUpload(io.BytesIO(file_content), mimetype='text/plain')
file = service.files().create(body=file_metadata, media_body=media, fields='id').execute()
# How to make this file public?
return file.get('id')
Any tips on how to tweak this to make the file public? Thanks!
I faced a similar issue in my project and found that the solution involves adding a permission right after the file is created. Once you create the file, you’ll need to execute a second API call that uses the ‘permissions()’ resource to set the file to be accessible by ‘anyone’ with ‘reader’ privileges.
For example, after creating the file, you can do the following:
permission = {
'type': 'anyone',
'role': 'reader'
}
service.permissions().create(fileId=file['id'], body=permission).execute()
This will ensure that the file is publicly accessible without requiring additional permissions. Just be mindful of the security implications when using public access rights.
yep, u can totally make files public with the drive api! after creating the file, just add this:
service.permissions().create(
fileId=file[‘id’],
body={‘type’: ‘anyone’, ‘role’: ‘reader’}
).execute()
that’ll make it visible to everyone. just be careful not to share sensitive stuff!
I’ve dealt with this exact issue in a project I worked on recently. The key is to use the permissions().create() method after you’ve uploaded the file. Here’s how I modified my create_public_file function to make it work:
def create_public_file(service, file_name, file_content):
file_metadata = {'name': file_name}
media = MediaIoBaseUpload(io.BytesIO(file_content), mimetype='text/plain')
file = service.files().create(body=file_metadata, media_body=media, fields='id').execute()
# Make the file public
service.permissions().create(
fileId=file['id'],
body={'type': 'anyone', 'role': 'reader'},
fields='id'
).execute()
return file.get('id')
This approach worked like a charm for me. Just remember to be cautious about what you’re making public, as it could potentially expose sensitive information if you’re not careful.